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4.9x^2-96.41x-500=0
a = 4.9; b = -96.41; c = -500;
Δ = b2-4ac
Δ = -96.412-4·4.9·(-500)
Δ = 19094.8881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96.41)-\sqrt{19094.8881}}{2*4.9}=\frac{96.41-\sqrt{19094.8881}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96.41)+\sqrt{19094.8881}}{2*4.9}=\frac{96.41+\sqrt{19094.8881}}{9.8} $
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